Refer to ohm's law given in the previous question. if the voltage in a circuit is 35+j12 volts and the resistance is 2+j4 ohms, what is the current? a) −596+j293 amps b) −196+j293 amps c) 33−j8 amps d) 5910−j295 amps e) 37+j16 amps f) 118−j164 amps

Ohm's Law:  voltage = resistance times current.  Here we know voltage and resistance, but must calculate the current.

current = voltage / resistance

                            35 + 12j

Here, current = amps

                           2(1+2j)

We must rationalize the denominator (remove 'j' from the denom.).  To do this, multiply numerator and denominator of the above fraction by (1-2j), obtaining:

(25+12j)(1-2j)       25-50j+12j+24        49 - 36j

= = ohms (answer)

2(1 + 4)                         10                       10

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

you can't solve x because it is 2 linear equation and you only have one equation