Two cyclists, 80 miles apart, start riding toward each other at the same time. one cycles 3 times as fast as the other. if they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

The speed of the faster cyclist will be 30 miles/hour.

Explanation

One cyclist is 3 times as fast as the other.

Lets assume that the speed of the slower cyclist is   miles/hour.

So, the speed of the faster cyclist will be:   miles/hour.

They start riding toward each other at the same time and meet 2 hours later.

We know that,  

So, the distance traveled by slower cyclist in 2 hours miles and the distance traveled by faster cyclist miles.

Given that, they were 80 miles apart at the starting. So, the equation will be.....

So, the speed of the faster cyclist will be: (3×10)= 30 miles/hour.

b and c

step-by-step explanation: