Apair of dice is rolled. find the probability of rolling a sum not less than 3

A pair of dice is rolled. Two dice are rolled

Possible outcomes are

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

So total of 36 outcomes

Question says 'the probability of rolling a sum not less than 3'

we look at the pair that has sum greater than or equal to 3

There is only one pair (1,1) whose sum is 1+1 =2

So we ignore (1,1) pair

Remaining 35 pairs have sum greater than 3

the probability of rolling  = (number of times event occurs)  divide by total number of outcomes

the probability ( rolling a sum not less than 3) =

ans789

step-by-step explanation:

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.