Item 3 find the sum. −1/2(7z+4)+1/5(5z−15)

We are given : −1/2(7z+4)+1/5(5z−15)

Solution: We have -1/2 in front of parenthesis (7z+4)  and 1/5 in front of parenthesis (5z-15).

That represents multiplication of -1/2 by (7z+4) and multiplication of 1/5 by (5z-15).

So, we need to distribute -1/2 over (7z+4) and 1/5 over (5z-15).

Therefore, −1/2(7z+4)+1/5(5z−15) = -1/2 * 7z -1/2 *4 +1/5*5z + 1/5* -15.

On simplifying this step, we get

-7/2 z - 2 + z -3.

Now, we need to combine like terms.

We have like term of -7/2 z is z and like term of -2 is -3.

Let us add those like terms.

-7/2 z + z:  z could be written as z/1 to add with fraction -7/2 z.

Therefore, -7/2 z + z/1 = -7/2 z + 2z/2     (we took common denomiator here)

= (-7+2)z/2

= -5/2 z.

-2 -3 = -5.

Therefore,

-7/2 z - 2 + z -3 = -7/2 z +z -2-3

= -5/2 z -5.

So, the final answer is  -5/2 z -5.

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )

step-by-step explanation:

a cube has 6 sides

the probability of getting 5 on the first cube is 1/6 since only one side of the cube has 5 on it.

there are 3 sides of the cube with even number on it [2,4,6]

therefore the probability of getting even number is 3/6

for both events to happen together, the probability would be

1/6 x 3/6 = 12/36

which simplifies to 1/12