What value of x is in the solution set of 3(x – 4) ≥ 5x + 2? –10 –5 5 10

First, distribute 3 to all terms within the parenthesis

3(x - 4) = 3x - 12

3x - 12 ≥ 5x + 2

Isolate the x. Subtract 5x from both sides, and add 12 to both sides

3x (-5x) - 12 (+12) ≥ 5x(-5x) + 2 (+ 12)

3x - 5x ≥ 2 + 12

Simplify

-2x ≥ 14

Isolate the x. Divide -2 from both sides. Note that when dividing a negative number, you must flip the sign.

-2x/-2 ≥ 14/-2

x ≥ 14/-2

x ≤ -7

x ≤ -7 is your expression. Any number equal too, or less than -7 is your answer

–10 is your answer

hope this helps

the answer is -10 that's the right answer

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

answer: the answer is e

step-by-step explanation: