Openstudt what are the coordinates of the turning point for the function f(x) = (x − 2)3 + 1? (−2, −1) (−2, 1) (2, −1) (2, 1)

f(x) = (x - 2)^3 + 1

Find the derivative:-

f'(x) =   3(x -2)^2   This = 0 at the turning points:-

so 3(x - 2)^2 =  

giving x = 2 .  When x = 2     f(x)  =  3(2-2)^3 + 1 = 1

Answer is (2, 1)

mean, 40.6

step-by-step explanation: