Yasmin's puppy, maggie, weighed 14 ounces at birth. she doubled her birth weight in 10 days. assuming her growth is constant, how much will she weigh at various times in the first year?

we are given growth rate is  constnat

so, equation wil be straight line

Yasmin's puppy, maggie, weighed 14 ounces at birth

Let's assume weight after t days as w

t is time in days

so, we get (0,14)

She doubled her birth weight in 10 days

so, we get (10, 28)

Firstly, we will find slope

(0,14)

x1=0, y1=14

(10, 28)

x2=10 , y2=28

we can use it and find m

now, we can use point slope form of line

we know that

1 year =365 days

so, we can plug t=365

so, weight after 1 year is 525 ounces.........Answer

d

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841