How do you find a vector of length 10 in the direction of v equals=left angle 3 comma negative 2 right angle 3,−2?

Your vector will be 10 times the unit vector in that direction. The unit vector is found by dividing the given vector by its length.

|| <3, -2> || = √(3² +(-2)²) = √13

Your vector of length 10 is then

... V = (10/√13)<3, -2> = <(30/13)√13, (-20/13)√13> ≈ <8.32, -5.55>

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step-by-step explanation:

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.