Acashier at the homewood grill has $585 in $5 bills and $20 bills. the cashier has three times as many twenties as fives. how many $20 bills does the cashier have

Let us assume number of $5 bills = x.

Number of $20 is three times as many twenties as fives bills.

and number of $20 bills = 3x.

Total amount of all bills = $585.

$5 times number of x bills + $20 times number of 3x bills = $585.

5x + 20*3x = 585.

5x + 60x = 585.

Adding 5x+6x, we get 65x.

65x = 585.

Dividing both sides by 65.

65x/65 = 585/65.

x=9.

Therefore, number of $5 bills = 9.

Number of $20 is three times of number of $5 bills, that is 3*9 = 27.

Therefore, 9 are number of $5 bills and 27 are number of $20 bills.

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

after 1 year: 221 deer

step-by-step explanation:

30% of 170 is 51. 170+51=221