In october flowers cost $1.50 each. the october price was a 20% increase of the september price. what was the price of of the flowers in september

Let p represent the price of the flowers in Sept.

The price in Oct. was then p  plus 0.20p, or 1.20p = $1.50.

                                $1.50

Solving for p,  p = = $1.25

                                1.20

One would have paid $1.25 per flower in Sept. and 20% more, or $1.50, in October.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

c: lkllmn.

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