Given: △afd, m∠f=90° df=7√3 , m∠d=30° find: area of △afd

We need to find the area of a triangle whose one side and two angles are given.

The area of is .

In

From the trigonometric identities we have

Area of a triangle is given by

The area of is .

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Using the definition of the tangent function, you can find ...

... FA = DF·tan(30°) = (7√3)·(1/√3) = 7

Then the usual formula for triangle area can be used:

... Area = (1/2)bh = (1/2)·(7√3)(7)

... Area = (49/2)√3 square units

... ≈ 42.44 square units

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

yes

step-by-step explanation: