The length of a rectangle is 5 m longer than its width. if the perimeter of the rectangle is 46 m , find its area.

The sides of the rectangla are its length and width. We know the length is 5m longer than the width. Since we dont know the width, we can say that the width is x and the length is x+5.

The perimeter, as we know, is equal to the sum of all sides. We have two “length” sides and two “width” sides, so our equation is:

x + x + x+5 + x+5 = 46
Lets add all of this:
4x + 10 = 46
4x = 46-10
4x = 36
x = 36/4
x = 9

So our width is 9m and the length is 14m.

The area of a rectangle is width times length, so:
9*14=126m^2.

Idon’t exactly understand but i think dbc=rst