Aroom has dimensions of 10.0 ft × 20.0 ft × 8.00 ft. given that there are three feet in a yard, what is the volume of the room in yd

The volume of the room is 59.26 cubic yards.

Given

The length of the room is 10 feet.

The height of the room is 20 feet.

The breadth of the room is 8 feet.

The volume of the room is given by the product of height, breadth, and length of the room.

Then

Hence, the volume of the room is 59.26 cubic yards.

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SOLUTION - GIVEN - Room dimensions are 10.0 ft × 20.0 ft × 8.00ft

                                  1 yard = 3 feet

FIND OUT - Volume  of a room in yard

TO PROOF -  FORMULA

                     Volume of a cuboid = length × breadth × height

                       here   length =  10.0ft

                                  breadth =20.0ft

                                  height = 8.00ft

                        volume of the room =   10.0 ft × 20.0 ft × 8.00 ft

                                                         =  1600 ft^3

                        1 yard = 3 ft

                         1 ft = 1/3 yard

                        volume of  a room in yard =( 1600 ×1/3 ×1/3×1/3 ) yard^3

                                                                   = 59.26 yard^3 (approx)

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.