Eight teams are competing in the quarter-finals of a world football championship title. three out of them are european. if the teams are paired randomly, what is the probability that none of the european teams have to play against each other?

P(none of them Europeans play against each other)=

Explanation:

Since there are 8 teams in which 3 are Europeans.

So, remaining 5 teams are not Europeans

We have to take 2 teams to pair up.

And we have a condition that neither of team is European.

So the favourable outcome =

and the total outcomes=

So, by using theprobability formula i.e.

P(E)=

P(getting none of European team play against each other)=

=

=

5/12, or 5: 12

step-by-step explanation:

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.