The length of a rectangle is 4 more than 3 times the width. if the perimeter of the rectangle is 56, what is the length of the rectangle

The relation between the width and the length is : l = 3w +4 -- eqn (1)  Perimeter = 56  » 2w + 2l = 56  Dividing through by 2 gives;  w + l = 28  w = 28 - l  -- eqn(2)  Substitute eqn (2) in eqn (1)  » l = 3(28-l) +4 Expanding bracket gives;  l = 84 - 3l +4 Grouping like terms , we have;  l + 3l = 84+4  4l = 88 l = 88/4  l = 22 The length of the rectangle is 22 units.

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step-by-step explanation:

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6