What is the midpoint of j(-4, 2), f(5, -2)

1/2, 0

To find this, use the midpoint formula:

(x1 + x2 all over 2 , y1 + y2 all over 2)

Insert the points in the correct location to come with the final answer of 1/2, 0.

Hope this helps!

i need more information

step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."