The school is hosting a pet show. there is a total of 110 dogs, cats, and hampsters in the show. if there are twuce as many dogs as thrre are cats, and ten fewer hamosteres than cats, how many cats are in the show

So, we know that there is a toatal of 110 dogs, cats, and hamsters. So let T equal 110. T=110

2d(cats)

(cats)-10h

Let me know if you need help to solve it, I cant go any further without the number of dogs.

There are 30 cats, 60 dogs and 20 hamsters.

rounding to the nearest thousandth would be 452,000

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560