Is the relationship between the variables in the table a direct variation, an inverse variation, or neither? if it is a direct or inverse variation, write a function to model it. x -6,-4,-3,1 y -72,-47,-36,12

neither direct variation nor inverse variation.

Explanation:

1) The relation between two variables, y and x, is a direct variation if and only if the quotient between them, y/x, is constant. This is: y / x = k or, equivalently, y = kx.

Note that if y / x is constant, x / y is also constant.

In a direct variation, when x increases, y increases, and when x decreases, y decreases.

2) The relation between two variables, y and x, is an inverse variation if and only if their product, y×x is constant. This is: y × x = k or, equivalently y = k /x or x = k / y.

In an inverse variation when one of the variables increases the other decreases.

3) Writhe the given table and study whether the conditions for direct or inverse variation are met:

x      y              y/x                             y×x

-6    -72           -72/(-6) = 12             (-6)(-72) = 432

-4    -47           -47 / (-4) = 11.75       (-4)(-47) = 188

-3    -36           -36 / (-3) = 12           (-3)(-36) = 108

1       12             12 / 1 = 12                (1)(12) = 12

Conclusions;

a) Since neither y / x nor y×x have the same result for every pair, the relation is neither direct nor inverse.

b) Note that if the third pair were (-4, -48) instead of (-4, -47), y / x would be 12, which make a direct variation. In this case the function that modeled it would be:

         y = 12x.

3,750 deer

step-by-step explanation:

1,500 is 15 times larger than 100

lets make 250 15 times larger.

3750 deer

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²