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![(x-1)(x-2)^2-(x-1)^2(x+2)\\\\=\boxed{(x-1)(x-2)}(x-2)-(x-1)\boxed{(x-1)(x+2)}\\\\=(x-1)(x-2)[(x-2)-(x-1)]\\\\\ (x-1)(x-2)=x^2-3x+2](/tpl/images/0072/9091/8809c.png)
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