Mike went to a football game with his family. they bought 5 boxes of popcorn and 3 programs, and spent $41. sean's family went to the same game, bought 3 boxes of popcorn and 2 programs, and spent $26. how much does each program cost at the game? (1 point) $4 $5 $6 $7

Let the price of a box of popcorn = b and the price of a program = p
we can make 2 equations:
5b+3p = 41 and 3b+2p=26

We can use the subtraction method be able to eliminate one of the variables and isolate the other one - to do it I will equalize the 'b' in both equations by multiplying by 5 and 3 respectively

5(3b+2p=26)
-3(5b+3p = 41)

15b+10p=130
-(15b+9p=123)

p=7 (therefore the answer is 7$)

For a 0.25 pfor b o.3pp (0.25+0.3)=0.28