Which statement correctly compares two values? a)the value of the 7 in 37.596 is 1/10 the value of the7 in 26.74 b) the value of the 7in 37.596 is 10 times the value of the 7 in 26.74 c) the value of the 7 in 37.596 is 1/100 the value of the 7in 26.74 d) the valueof the 7 in 37.596 is 100 times the value of the 7 in 26.74 explain the reasoing of this answer

The value of 7 in 26..74 is 0.7

The value of 7 in 37.596 is 7.

1/10 the value of 7 in 26.74 is 0.07 and 0.07 ≠ 7.

So, statement a) is incorrect.

1/100 the value of 7 in 26.74 is 0.007 and 0.007 ≠ 7.

So, statement c) is incorrect.

100 times the value of 7 in 26.74 is 70 and 70 ≠ 7.

So, statement d) is incorrect.

10 times the value of 7 in 26.74 is 7 and 7 = 7.

So, statement b) is correct and it correctly compares two values.

step-by-stp

the correct answer is the section c

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).