Mathematics, 10.07.2019 21:30 gonzmari457
(n+1)^3-n^3=1+3 (n+1)n using this formulae find the cube of 999.if cube of 1000 is 1000000000.
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One integer is 8 times another. if the product is 72, then find the integers
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(n+1)^3-n^3=1+3 (n+1)n using this formulae find the cube of 999.if cube of 1000 is 1000000000....
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