What would 2x + 3y = 1,470 be in slope intercept form and how do you get it

slope intercept formula is y = mx + b.

Isolate the y. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 2x from both sides

2x (-2x) + 3y = (-2x) + 1470

3y = -2x + 1470

Isolate the y. Divide 3 from both sides

(3y)/3 = (-2x + 1470)/3

y = (-2x + 1470)/3

Simplify

y = (-2/3)x + 490

y = (-2/3)x + 490 is your answer

hope this helps

i know the answer is 3

step-by-step explanation:

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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