In still air a bird flies 36 miles per hour with the wind it travels 6 miles farther in 3 hours then it flies in 6 hours against the wind, in miles per hour? round your answer to the nearest tenth

Let v be the speed of wind.

1. With the wind a bird flies 3 hours. The speed of bird with the wind is 36+v mi/h.

Then it flies the distance

miles.

2. Against the wind a bird flies 6 hours with the speed 36-v, then it flies the distance

miles.

3. If with the wind a bird travels 6 miles farther than against wind, you have an equation

4. Solve it

5. You find the speed of the wind mi/h. Then a bird:

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

at least two

step-by-step explanation: