Question james and bethany morrison are celebrating their 10th anniversary by having a reception at a local reception hall. they have budgeted $ 4 comma 500 $4,500 for their reception. if the reception hall charges a $100 cleanup fee plus $35 per person, find the greatest number of people that they may invite and still stay within their budget.

Let x = greatest number of people they can invite , then:-

35 x + 100 ≤ 4500

35x ≤ 4400

x  ≤  125.7

so the answer is 125 people

146%

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3