Find the x-value at which f is not continuous. is the discontinuity removable?

Your teacher has decided to break down the problem into smaller chunks. The function f(x) will depend on what the x value is. If x is 2 or smaller, then f(x) = -6x as shown in the top row of the piecewise function. If x is larger than 2, then f(x) = x^2-7x+7.

So you'll put a -6 in the box for your image attachment to start off so you tell your teacher that f(x) = -6x when x = 2. Afterwards, plug x = 2 into f(x) = -6x to get f(2) = -12. Then plug x = 2 into f(x) = x^2-7x+7 to get -3. Since this value is not -12, this tells us we have a discontinuity at x = 2. This is a jump discontinuity as shown in the image attachment shown below. Note the closed circle at (2,-12) and the open circle at (2,-3). The open circle means "exclude this point from the graph".

hope this .

r3t40

the system of inequity is

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

the solid line passing through the points (0,4) and (4,0).

the related equation of solid line is .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

the related equation of dashed line is

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be . the required inequality is

similarly, check the second related equation.

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is