Point p is in the interior of ∠ozq. if m∠ozq = 125° and m∠ozp = 62°, what is m∠pzq?

The measure of  m∠PZQ is 63degrees

The point where two lines meet or intersect is known as an angle.

If point P is in the interior of ∠OZQ, then:

<OZQ = <OZP +  m∠PZQ

Given the following angles:

m∠OZQ = 125°

m∠OZP = 62°

Substitute the given values into the expression above:

125 = 62 +  m∠PZQ

m∠PZQ = 125 - 62

m∠PZQ = 63degrees

Hence the measure of  m∠PZQ is 63degrees

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Step-by-step explanation:

We are given that point P is interior of angle OZQ.

We are given that angle OZQ =

The measure of angle OZP=

Angle OZQ=Angle OZP+Angle PZQ

Substitute the values

Then, we get

Using by subtraction property of equality

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

72 is the answer to this problem