In the figure a b c and d reflect across ef to coincides with points g j i and h respectively

∠GHI = 90° and coordinates of point K will be (8, -6)

Step-by-step explanation:

The given figure ABCD is reflected across EF to coincide with the points G, J, I and H.

We have to tell the measurement of ∠GHI. After reflection image formed by G,J,I and H will be similar.

Therefore ∠GHI = 90°

Now this figure GHIJ is reflected across x-axis then we have to find the coordinates of new point G.

Since point G(8, 6) is lying in the first quadrant, when reflected across x axis the new point K lies in 4th quadrant and the coordinates of K will be (8, -6).

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer is : muchas/tipicas

have a nice day!

~recklesschicken