Dafes stickball team has six players. how many different six player battling lineups can they make ifdave must bat second and either zack or paul must bat first

Let us name the players A,Dave,Zack,Paul,E and F 
For the first position there are two candidades ( Zack / Paul ) 
For the second position there is only one candidate i.e. Dave 
For the third place there will be 4 candidates (out of Zack and Paul - 1 as one of them is already taken for the first position and A, E and F total-4) 
For the fourth place there will be 3 candidates ( out of the four available candidates in the 3rd place, one will be taken up for 3rd place ) 
For the fifth place there will be 2 candidates 
Finally, for the last place there will be only one candidate left. 
On multiplying the no. of available cadidates, we get 2 * 1 * 4 * 3 * 2 * 1 = 48 i.e. option (A) 
Please mention minor spelling mistakes 
For the second question: 
Let the no of dotted marbles be 'x' and no of striped marbles be 'y' 
then the equation will become as follows 
(y+6)/x = 3 
and 
(x+6)/y = (2/3) 
On solving the equations, we will get x = 10 and y = 24 
Total balls = 10+24+6 = 40 (option E) 
Answer 3 will be ) For the first edge, he can choose 3 paths 
For the second edge he can choose 2 paths for each path of its first edge's path 
For the third , he is bounded to move on the paths created by the first and the second edges hence 1 path for each path created by the first and the second edge together 
It will be multiplication of all the possibilities of the paths of the three edges differently 
i.e. 3 * 2 * 1 = 6