The sum of age of mabel and fred is 38 years, four years ago the age of mabel was the square of fred age. find their ages

m+f=38

(f-4)^2=m-4

f^2=m IF their age is 30 combined

4^2=16

16=16

Fred is 4, Mabel is 16.

answer: a. 74

step-by-step explanation:

it shows divided evenly, so add the 37+37 = 74

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)