Twice the difference of a number and 2 is equal to three times the sum of the number and 3. find the number. the number is nothing.

The number is -13.

In order to find this, we first need to make each part of the statement into a mathematical statement.

Twice the difference of a number and 2.

2(x - 2)

Three times the sum of the number and 3

3(x + 3)

Now we can set them equal to each other and solve.

2(x - 2) = 3(x + 3) > Distribute

2x - 4 = 3x + 9 > Subtract 2x from both sides

-4 = x + 9 > Subtract 9 from both sides

-13 = x

i believe the correct answer is b.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it