At carters birthday his mom baked a cake in a rectangular shape. the lenght of cake is 8 cm and the width of it is 6 cm. if he wants to add 1 cm of cream around the cake what would be the perimeter and area. teacher hint: use a scale drawing need i have a b in math

First of all, let's remember the formula for calculating area. Length times width equals area. (lxw=a)

Now that we have the formula. Let's take the length (8 cm) and the width (6 cm) and add 1 cm to each of them.

Length: 8+1=9.

Width: 6+1=7.

Now, let's apply the formula for area.

9 x 7 = 63

Now that we've found the area is 63 cm, let's find the perimeter. To find the perimeter of a rectangle, we must multiply the length by 2 and the width by 2, then we add the two numbers. In this case, here's what we'll do:

9 x 2 = 18

7 x 2 = 14

18 + 14 = 32

Now we have the area and perimeter.

Final answer(s):

Area = 63 cm.

Perimeter = 32 cm.

Hope this explanation helped you out. :)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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