Dr. abramson and her assistants are working on three different experiments using water. each experiment lasts for 15 minutes. for the fi rst experiment, the water level must be checked every 12 seconds. for the second experiment, the temperature of the water must be checked every 30 seconds. for the third experiment, the color of the water must be checked every 36 seconds. in minutes, list the times all three experiments will need to be checked at the same time.

The correct answer is:

Every 6 minutes.

Explanation:

To find the intervals in which each of the 3 experiments must be checked at the same time, we must find the least common multiple of all 3 numbers.  To do this, we find the prime factorization of each:

12 = 6(2)

6 = 2(3)

12 = 2(2)(3)

30 = 10(3)

10 = 2(5)

30 = 2(3)(5)

36 = 6(6)

6 = 2(3)

6 = 2(3)

36 = 2(2)(3)(3)

We first find the common factors.  Between all 3 numbers, the only common factors are 2 and 3.

Next we multiply these common factors by the uncommon ones.  The uncommon factors are 2, 2, 5 and 3:

2(3)(2)(2)(5)(3) = 6(2)(2)(5)(3) = 12(2)(5)(3) = 24(5)(3) = 120(3) = 360

This means the least common multiple is 360.  360/60 = 6; this means every 3 minutes all 3 experiments will need to be checked.

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step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v