Arectangle is 12 feet long and five feet wide. if the length of the rectangle is increased by 25% and the width is decreased by 20%, what is the change in the area of the rectangle

First of all, let's single out the 12 feet long and the 5 feet wide. We need to figure out what 25% of the length (12 feet) is. Let's divide 12 by 4. We get 3. Now, let's remember that.

Second, we need to figure out what 20% of the width (5 feet) is. Let's divide 5 by 5. We get 1. Now, let's also remember that number.

Now, we must add the numbers we got to the original length and width. For 12, we got 3, and 12+3=15. For 5, we got 1, and 5+1=6.

Now that we have the new length (15) and the new width (6), we must multiply to find the new area. 15x6=90. Using the original length (12) and the original width (5) we will multiply to find the original area. 12x5=60.

Original Area: 60 feet.

Area after increasing length and width: 90 feet.

Change in area: 30 feet.

I hope this explanation helped you out so that you can do it yourself next time. If you need anymore help, feel free to message me.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2