In △abc, m∠cab = 60° and ad is angle bisector with d∈ bc and ad=8ft. find the distances from d to the sides of the triangle.

The distances from D to the both sides(AB and AC) of the triangle are 4 ft.

Explanation

In the diagram below, ABC is a triangle in which ∠CAB = 60°

As,  AD is the angle bisector of ∠CAB, that means ∠CAD = ∠DAB = 30°

The distance from D to side AC is  DE and distance from D to side AB is  DF. That means both ∠AED and ∠AFD are right angle.

Given that, the length of AD = 8 ft.

So, in right angle triangle AED.....

Also, in right angle triangle AFD....

So, the distances from D to the both sides(AB and AC) of the triangle are 4 ft.

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )