The body of a 154 pound person contains approximately 4 × 10-1 milligrams of gold and 16 × 101 milligrams of aluminum. based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

The number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

Explanation

Lets assume, the number of milligrams of aluminum is times the number of milligrams of gold in the body.

The body of a 154 pound person contains approximately 4 × 10⁻¹ milligrams of gold and 16 × 10¹ milligrams of aluminum.

So the equation will be...

So, the number of milligrams of aluminum is 400 times the number of milligrams of gold in the body.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

i think it is c, not positive though

step-by-step explanation: