Find the fourth term of the expansion (5 + 3y)^5

(r+1)the term of (a + b)^n

= nCr a^(n-r) b^r

So 4th  term  = (3 + 1)th term) of (5 + 3y)^5=

5C3 (5^(5-3) (3y)^3

= 10*  25 * 27y^3

= 6750 y^3   answer

answer: i think it's a

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length