a store runs a promotion in which every 500th  customer (500th, 1000th, 1500th, received a free gift, every 800th  (800th, 1600th, customer receives a voucher, and every 1200th  (1200th, 2400th, customer receives a discount. which lucky customer will be the first to receive all three promotional prizes?

The answer is 12,000

To solve this question, you have to find the least common multiple of the three promotional prizes. The factor of 500, 800 and 1200 would be:

500= 2*2*5*5*5= 2^2 * 5^3

800= 2*2*2*2*2*5*5= 2^5 * 5^2

1200= 2*2*2*2*3*5*5= 2^4 * 3 *5^2

The LCM of those three number would be: 2^5 * 3 * 5^3= 12,000

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0