Find the perimeter p of ▱jklm with vertices j(2,2), k(5,3), l(5,−3), and m(2,−4). round your answer to the nearest tenth, if necessary.

Consider the vertices of parallelogram JKLM with vertices J(2,2) , K(5,3) , L(5,-3) and M(2,-4).

Perimeter JKLM = Length JK + Length KL + Length LM + Length JM

Length JK = (2,2) (5,3)

The length(or distance) between two points say and is given by the distance formula:

Now, length JK =

= units

Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.

Therefore, LM =   units

Now, length KL =

= 6 units

Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.

Therefore, JM =  6 units

Perimeter of JKLM =   +   + 6 + 6

= 2 + 12

= 18.324

Rounding to the nearest tenth, we get

= 18.3 units.

Therefore, the perimeter of JKLM is 18.3 units.

step-by-step explanation:

dong do iy iys a scram

linear pair postulates