Arectangle has an area of 102cm2 the length of the rectangle is 17 cm what is the perimeter off the rectangle

Hello!

The area of rectangle is found by multiplying the width and the length of the rectangle together.

Given the area, 102 centimeters squared and the length of the rectangle, which is 17 centimeters, we need to find the width of the rectangle. To find the width, substitute the given values and solve for w, or the width.

102 = 17w (divide both sides by 17)

w = 6 | The width of the rectangle is 6 centimeters.

With that, the perimeter of the rectangle is found by using the formula:

P = 2l + 2w

In this formula, l is the length, and w is the width. Since we have the values, we can substitute the values into the formula and simplify.

P = 2(17) + 2(6)

P = 34 + 12

P = 46

Therefore, the perimeter of the triangle is 46 centimeters.

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer