Xis a number from the set [3,5,6] and y is a number from the set [4,7,8,9]. if xz/y is an integer and z is a positive integer, what is the lowest possible value of z? a) 1 b) 2 c) 3 d) 4 plzz !

The smallest possible value of z is the denominator of the reduced fraction x/y. We note the prime factors of the members of set y are

... 2², 7, 2³, 3²

so if there are any even members of set x, the fraction can be reduced to something divided by 2. The number 6 in set x is even, so we have

... 6z/4 = 6·2/4 = 3 (an integer) when z=2

The lowest possible value of z is ...

... B) 2

answer is : muchas/tipicas

have a nice day!

~recklesschicken

1 1/5

step-by-step explanation: