Range of f(x)=-x+5 with domain of [-3,2] in the same notation as the domain.

The range would be [8, 3]

In order to find the range, simply plug each end of the domain into the equation.

f(x) = -x + 5

f(-3) = -(-3) + 5

f(-3) = 3 + 5

f(-3) = 8

Then the other side

f(x) = -x + 5

f(2) = -2 + 5

f(2) = 3

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)