Arectangular deck is to be built so that the width and the length are two consecutive even integers and the perimeter is 252 ft. find the dimensions of the deck.

Dimensions of the rectangular deck are 64 feet × 62 feet.

Step-by-step explanation:

Let the length of the rectangular deck = l ft

And the width of the rectangular deck = w ft

Since width and length of the deck are two consecutive even integers,

so,  l = w + 2

Now perimeter of the rectangular deck has been given = 252 ft

Then by the formula,

Perimeter = 2 (length + width)

252 = 2(l + w)

252 = 2[w + (w + 2)]

252 = 2(2w + 2)

252 = 4(w + 1)

w + 1 =

w = 63 - 1

w = 62 ft

Sine l = w + 2

l = 62 + 2

l = 64 ft

Therefore dimensions of the deck are 64 feet × 62 feet.

1010: 3030

is it i think