Aball is dropped from a height of 36 feet. at each bounce the ball reaches a height that is three quarters of the previous height. how many bounces must the ball make before it rebounds less than 1 foot?

Ball will make 13 bounces before it rebounds less than 1 foot.

Step-by-step explanation:

A ball is dropped from a height of 36 feet.

In each bounce the ball reaches a height that is three quarters of the previous height.

Sequence formed will be 36, 27, 20.25.........

This sequence has a common ratio of

Therefore, sequence will be a geometric sequence.

Explicit formula of this sequence will be

where a = first term of the sequence

r = common ratio

n = number of term

For this sequence formula will be

If this term is less than 1

Taking log on both the sides

1.5563 + n(-0.1249) < 0

0.1249n > 1.5563

n >

n > 12.46

n ≈ 13

Therefore, ball will make 13 bounces before it rebounds less than 1 foot.

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)