The shells fired from an artillery piece have a muzzle speed of 225 m/s, and the target is at a horizontal distance of 1.20 km. two possible angles can be used to hit the target. find the smallest angle relative to the horizontal at which the gun should be aimed? (hint: sin2θ = 2sinθcosθ)

The parametric equations for shell position are ...

... (x, y) = (v₀·cos(θ)t, -(1/2g)t²+v₀·sin(θ)t)

with conditions

... v₀ = 225 m/s

... g = 9.8 m/s²

The value of θ in the range 0–45° that makes (x, y) = (1200, 0) m for t > 0.

Solving the x equation for t, we have

Substituting this into the equation for y gives

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

$9.41

step-by-step explanation: