Solve the system of equations below by graphing both equations with a pencil and paper. what is the solution? y=x-1 y=1/2x+1 ,-3) b.(4,3) c.(2,1) ,0)

The graph doesn't have to be very sophisticated to come to the correct choice of those offered. Both lines have positive slope, and the one with the least slope has a positive y-intercept. The solution must be in the first quadrant, and must have a y-value greater than 1.

The appropriate choice is

... B. (4, 3)

Option B is correct.

Step-by-step explanation:

Given Equation of lines are

y = x - 1 ...................(1)

y = 1/2x + 1 ...............(2)

To draw them on line, we find two points or solution of line.

Consider, line 1

put x = 0                                    

we get, y = 0 - 1 = -1                

Now, put x = 1

we get, y = 1 - 1 = 0  

So the required point of line 1 are ( 0 , -1 )  and ( 1 , 0 )

Consider, line 2

put x = 0                                    

we get, y = 0 + 1 = 1                

Now, put x = -2

we get, y = -1 + 1 = 0  

So the required point of line 2 are ( 0 , 1 )  and ( -2 , 0 )

Now we graph graph using obtained point.

Graph is attached.

Clearly from the graph, Point of intersection is ( 4 , 3 )

Therefore, Option B is correct.

maybe - definition of supplementary angles. im not sure. sorry

step-by-step explanation: