(1.)what is the value of 35−3m , when m = 4? a.1 b.13 c.23 d.128 (2.)what is the value of 1 + x ÷ 5, when x = 80? enter your answer in the box. (3.)evaluate the expression for the given values. mx−y when m=5, x=3, and y=8 enter your answer in the box. (4.)evaluate 3a+15+bc−6, when a=7, b=3, and c=15. enter your answer in the box.

1.) 35-3m

m= 4

35-3m

= 35-3(4)

= 35-12 (do the multiple/division first before doing the addition/subtraction)

= 23

C. 23

(2.) 1 + x ÷ 5

x = 80

1 + x ÷ 5

= 1+80÷5

= 1+16

= 17

(3.) mx-y

m=5, x=3, and y=8

mx-y

= 5(3)-8

= 15-8

= 7

(4.) 3a+15+bc−6

a=7, b=3, and c=15

3a+15+bc-6

= 3(7)+15+3(15)-6

= 21+15+45-6

= 75

Step-by-step explanation:

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6