The sum of three consecutive even integers is 162 as an algebraic equation ?

F(x)= x + (x+1) + (x+2)
162= x + (x+2) + (x+4)
Solve for x and x will be equal to the first integer

Solved:
162= x + (x+2) + (x+4)
162= 3x + 6
156= 3x
52= x
The consecutive integers will be 52, 54, 56

I'm just guessing, but my answer would c. 0 to 300.