Pq=2x-3. if qr=5x+7 and pr=10x-11, then pr=?

Given: PQ=2x-3. if QR=5x+7 and PR=10x-11

To Find: PR

Solution: From the attached diagram, point P, Q and R are co-linear.

Hence,       PR = PQ + QR

or,         10x-11 = 2x-3 + 5x+7

or,      10x - 7x = 15

or,                 x = 5

Now, we shall calculate the value of PR

                 PR = 10x-11

or,              PR = 10× 5 - 11

or,              PR = 39

Hence, the required value of PR will be 39.

the correct answer is b. negative exponential growth.

step-by-step explanation:

you can tell it's an exponential function because it decreases rapidly then levels out and never touches the x-axis.

it is negative because the y-axis decreases as the x-axis increases.

therefore it is a negative exponential growth graph.

hope i !

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.