Can somone plz solve this for me. i kinda still dont understand it

First one uses elimination, as you have already done, allowing you to find Y. You keep going and add the x’s and numbers together as well getting

6y = 12
Divide the 6

Y = 2

To find X just pick one of the ORIGINAL equations (doesn’t matter which) and plug in 2 for why and solve for x

Ex: 3x + 2(2) = 7

3x + 4= 7
Subtract 4

3x= 3
Divide 3

X = 1

Then check to see if it’s correct by plugging both in for the second equation.

-3(1) + 4(2) =5

5=5 both work
so your answer is (1,2)

For your second one you can solve by substitution or by elimination, however, because y is by itself substitution would be easier.

5x + 2y = 7
-4x + y = -16

Get y by itself for the second equation by adding 4x to each side (because 4x is negative and you need to cancel it) making:

Y= 4x - 16

you then replace this equation in where y is in the first one

5x + 2(4x - 16) = 7

Distribute the 2

5x + 8x - 32 = 7

Combine like terms (and add 32 to both sides)

13x = 39
Divide 13

X = 3

Go back to the ORIGINAL equations and replace x in any one.

5(3) -2y =7

15 - 2y =7
Subtract 15

-2y = -8
Divide - 2

Y=4

And check to make sure (3,4) is correct by plugging in

-4(3) - 4 = -16

-12 -4 = -16

-16 = -16

(3,4) works

I’ll you if you answer my questions!